java解析request或url中的参数工具类代码
转载 2019-11-05 21:21 阅读(2545)次
无论我们在做爬虫时还是在做访问日志解析时，都需要java获取request中的参数、java解析URL问号后的参数。有时候我们需要从request中获取参数，或者获取拼接在Url后面的参数，有时候一个一个去拿有点麻烦，一起拿出来放在一个map里面需要用哪个就取哪个，方便省事
代码转载https://www.bbsmax.com/A/GBJrq74Wz0/
上代码：
import java.io.UnsupportedEncodingException;
import java.net.URLDecoder;
import java.util.HashMap;
import java.util.Map;
import javax.servlet.http.HttpServletRequest;
public class HttpParamUtil {
/**
* 获得url中参数
* @param url
* @return
*/
public static Map<String, Object> getParameter(String url) {
Map<String, Object> map = new HashMap<String, Object>();
try {
final String charset = "utf-8";
url = URLDecoder.decode(url, charset);
if (url.indexOf('?') != -1) {
final String contents = url.substring(url.indexOf('?') + 1);
String[] keyValues = contents.split("&");
for (int i = 0; i < keyValues.length; i++) {
String key = keyValues[i].substring(0, keyValues[i].indexOf("="));
String value = keyValues[i].substring(keyValues[i].indexOf("=") + 1);
map.put(key, value);
}
}
} catch (Exception e) {
e.printStackTrace();
}
return map;
}
/**
* 获取request中参数
*
* @param request 页面请求
*/
public static Map<String, Object> getRequestParameters(HttpServletRequest request) {
String parameters = "";// 请求参数
String urlParameter = request.getQueryString();// 网址中的参数
if (urlParameter != null && !"".equals(urlParameter)) {
try {
urlParameter = URLDecoder.decode(urlParameter, "UTF-8");
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
}
} else {
urlParameter = "";
}
parameters = urlParameter;
Map<String, Object> map = new HashMap<String, Object>();
String[] arr = parameters.split("&");
for (int i = 0; i < arr.length; i++) {
String key = arr[i].substring(0, arr[i].indexOf("="));
String value = arr[i].substring(arr[i].indexOf("=") + 1);
map.put(key, value);
}
return map;
}
/**
* 测试
*
* @param args
*/
public static void main(String[] args) {
String url = "www.xxxx.com?id=100001&name=zhangsan&age=25";
Map<String, Object> map = getParameter(url);
System.out.println(map);
}
}